Solve the inequality: \acxx−1<\acx+1x\ac{x}{x-1} < \ac{x+1}{x}\acxx−1<\acx+1x.
−1<x<0-1 < x < 0−1<x<0 or x>1x > 1x>1
x<−1x < -1x<−1 or 0<x<10 < x < 10<x<1
x>1x > 1x>1 or x<0x < 0x<0
−1<x<1-1 < x < 1−1<x<1