Solve the congruence: 5x≡7(mod12)5x \equiv 7 \pmod{12}5x≡7(mod12)
x≡11(mod12)x \equiv 11 \pmod{12}x≡11(mod12)
x≡7(mod12)x \equiv 7 \pmod{12}x≡7(mod12)
x≡5(mod12)x \equiv 5 \pmod{12}x≡5(mod12)
No solution exists