Solve the compound inequality: 1<3x−2\eq101 < 3x - 2 \eq 101<3x−2\eq10.
1<x\eq41 < x \eq 41<x\eq4
x>1x > 1x>1 and x\eq4x \eq 4x\eq4
−1<x\eq4-1 < x \eq 4−1<x\eq4
Both a and b