Solve the 3×33 \times 33×3 system: {x+y+z=62x−y+z=3x+2y−z=2\begin{cases} x + y + z = 6 \\ 2x - y + z = 3 \\ x + 2y - z = 2 \end{cases}⎩⎨⎧x+y+z=62x−y+z=3x+2y−z=2 What is the value of yyy?
y=1y = 1y=1
y=2y = 2y=2
y=3y = 3y=3
y=4y = 4y=4