Solve tan2(θ)=3\tan^2(\theta) = 3tan2(θ)=3 for θ∈[0,π)\theta \in [0, \pi)θ∈[0,π).
θ=π3,2π3\theta = \frac{\pi}{3}, \frac{2\pi}{3}θ=3π,32π
θ=π6,5π6\theta = \frac{\pi}{6}, \frac{5\pi}{6}θ=6π,65π
θ=π3\theta = \frac{\pi}{3}θ=3π
θ=π3,4π3\theta = \frac{\pi}{3}, \frac{4\pi}{3}θ=3π,34π