Solve x+2>x\sqrt{x+2} > xx+2>x.
−2≤x<2-2 \leq x < 2−2≤x<2
x<2x < 2x<2
x>−2x > -2x>−2
x<2x < 2x<2 and x≥−2x \geq -2x≥−2