Solve x2−1<2−x\sqrt{x^2 - 1} < 2 - xx2−1<2−x.
x≤−1x \leq -1x≤−1
x≤1.25x \leq 1.25x≤1.25
1≤x<1.251 \leq x < 1.251≤x<1.25
x≤−1x \leq -1x≤−1 or 1≤x<1.251 \leq x < 1.251≤x<1.25