Solve sin(2x)=cos(3x)\sin(2x) = \cos(3x)sin(2x)=cos(3x) for x∈[0,π/2]x \in [0, \pi/2]x∈[0,π/2].
π/10\pi/10π/10
π/5\pi/5π/5
π/10,π/2\pi/10, \pi/2π/10,π/2
π/10,π/6\pi/10, \pi/6π/10,π/6