Solve sinx+cosx=1\sin x + \cos x = 1sinx+cosx=1 for x∈[0,2π]x \in [0, 2\pi]x∈[0,2π].
0,π/20, \pi/20,π/2
π/2,π\pi/2, \piπ/2,π
0,2π0, 2\pi0,2π
π/4,5π/4\pi/4, 5\pi/4π/4,5π/4