Solve log2(x)+log2(x−3)=2\log_{2}(x) + \log_{2}(x-3) = 2log2(x)+log2(x−3)=2.
x=4x = 4x=4
x=−1,4x = -1, 4x=−1,4
x=1x = 1x=1
x=2x = 2x=2