Solve: x(x−3)x+2≤0\frac{x(x - 3)}{x + 2} \leq 0x+2x(x−3)≤0
(−2,0]∪[3,∞)(-2, 0] \cup [3, \infty)(−2,0]∪[3,∞)
(−∞,−2)∪[0,3](-\infty, -2) \cup [0, 3](−∞,−2)∪[0,3]
[−2,0]∪[3,∞)[-2, 0] \cup [3, \infty)[−2,0]∪[3,∞)
(−∞,0)∪(3,∞)(-\infty, 0) \cup (3, \infty)(−∞,0)∪(3,∞)