Solve: x−2x+3≥0\frac{x-2}{x+3} \geq 0x+3x−2≥0
x≤−3x \leq -3x≤−3 or x≥2x \geq 2x≥2
−3<x≤2-3 < x \leq 2−3<x≤2
x<−3x < -3x<−3 or x≥2x \geq 2x≥2
−3<x<2-3 < x < 2−3<x<2