Solve k+2k−2=k+5k+1\frac{k+2}{k-2} = \frac{k+5}{k+1}k−2k+2=k+1k+5.
k=3k = 3k=3
k=−3k = -3k=−3
k=4k = 4k=4
k=−4k = -4k=−4