Solve dydx=1x2\frac{dy}{dx} = \frac{1}{x^2}dxdy=x21 for x>0x > 0x>0 with y(1)=2y(1) = 2y(1)=2.
y=−1x+3y = -\frac{1}{x} + 3y=−x1+3
y=1x+1y = \frac{1}{x} + 1y=x1+1
y=−1x+2y = -\frac{1}{x} + 2y=−x1+2
y=ln(x)+2y = \ln(x) + 2y=ln(x)+2