Solve dydx=1x\frac{dy}{dx} = \frac{1}{x}dxdy=x1 for x>0x > 0x>0.
y=x+Cy = x + Cy=x+C
y=ln(x)+Cy = \ln(x) + Cy=ln(x)+C
y=1x2+Cy = \frac{1}{x^2} + Cy=x21+C
y=ex+Cy = e^x + Cy=ex+C