Solve dydx=ex+y\frac{dy}{dx} = e^{x+y}dxdy=ex+y with y(0)=0y(0) = 0y(0)=0.
y=−ln(2−ex)y = -\ln(2-e^x)y=−ln(2−ex)
y=ln(2−ex)y = \ln(2-e^x)y=ln(2−ex)
y=−ln(ex)y = -\ln(e^x)y=−ln(ex)
y=ex−1y = e^x - 1y=ex−1