Solve dydx=ex−y\frac{dy}{dx} = e^{x-y}dxdy=ex−y with y(0)=0y(0) = 0y(0)=0.
y=ln(ex)y = \ln(e^x)y=ln(ex)
y=ln(ex−1)y = \ln(e^x - 1)y=ln(ex−1)
y=ln(ex)y = \ln(e^x)y=ln(ex) is not correct, try y=ln(ex+C)y = \ln(e^x + C)y=ln(ex+C)
ey=ex+Ce^y = e^x + Cey=ex+C