Solve dydx=cos(x)\frac{dy}{dx} = \cos(x)dxdy=cos(x) with the initial condition y(0)=1y(0) = 1y(0)=1.
y=sin(x)+1y = \sin(x) + 1y=sin(x)+1
y=cos(x)+1y = \cos(x) + 1y=cos(x)+1
y=−sin(x)+1y = -\sin(x) + 1y=−sin(x)+1
y=sin(x)y = \sin(x)y=sin(x)