Solve for zzz: z=1+i(1−i)2z = \frac{1 + i}{(1-i)^2}z=(1−i)21+i.
−1+i2\frac{-1+i}{2}2−1+i
1−i2\frac{1-i}{2}21−i
i2\frac{i}{2}2i
1+i2\frac{1+i}{2}21+i