Solve for zzz: z2−(3+i)z+(2+i)=0z^2 - (3+i)z + (2+i) = 0z2−(3+i)z+(2+i)=0.
z=1z=1z=1
z=2+iz=2+iz=2+i
z=iz=iz=i
z=3z=3z=3