Solve for zzz: \ac12∣z+1∣<3\ac{1}{2}|z + 1| < 3\ac12∣z+1∣<3.
−7<z<5-7 < z < 5−7<z<5
−5<z<7-5 < z < 7−5<z<7
z<5z < 5z<5
z>−7z > -7z>−7