Solve for xxx: ∣x2−3∣<1|x^2 - 3| < 1∣x2−3∣<1.
x∈(−3,−2)∪(2,3)x \in (-\sqrt{3}, -\sqrt{2}) \cup (\sqrt{2}, \sqrt{3})x∈(−3,−2)∪(2,3)
x∈(−2,2)x \in (-2, 2)x∈(−2,2)
x∈(−2,2)x \in (-\sqrt{2}, \sqrt{2})x∈(−2,2)
x∈(2,2)x \in (\sqrt{2}, 2)x∈(2,2)