Solve for xxx: log3(x+1)+log3(x−1)=1\log_{3}(x+1) + \log_{3}(x-1) = 1log3(x+1)+log3(x−1)=1.
x=2x = 2x=2
x=4x = 4x=4
x=2x = \sqrt{2}x=2
x=0x = 0x=0