Solve for xxx: log2(x+3)+log2(x−1)=5\log_2(x+3) + \log_2(x-1) = 5log2(x+3)+log2(x−1)=5.
x=5x=5x=5
x=−5,1x=-5, 1x=−5,1
x=3x=3x=3
x=5,−7x=5, -7x=5,−7