Solve for xxx: log(x)+log(x−3)=1\log(x) + \log(x - 3) = 1log(x)+log(x−3)=1 (using base 10).
x=5x = 5x=5
x=−2x = -2x=−2
x=5x = 5x=5 or x=−2x = -2x=−2
No real solution