Solve for xxx: logx−1(x+1)=2\log_{x-1}(x+1) = 2logx−1(x+1)=2.
x=2x = 2x=2
x=3x = 3x=3
x=2x = \sqrt{2}x=2
x=1+2x = 1 + \sqrt{2}x=1+2