Solve for xxx: log7(x+3)−log7(x)=1\log_7(x + 3) - \log_7(x) = 1log7(x+3)−log7(x)=1
x=12x = \frac{1}{2}x=21
x=1x = 1x=1
x=36x = \frac{3}{6}x=63
x=3x = 3x=3