Solve for xxx: log3(x)=log3(12)−log3(4)\log_3(x) = \log_3(12) - \log_3(4)log3(x)=log3(12)−log3(4)
x=2x = 2x=2
x=3x = 3x=3
x=4x = 4x=4
x=8x = 8x=8