Solve for xxx: log2(x)+log2(x−2)=3\log_2(x) + \log_2(x-2) = 3log2(x)+log2(x−2)=3. Which of the following values are solutions?
x=4x = 4x=4
x=−2x = -2x=−2
x=1x = 1x=1
x=0x = 0x=0