Solve for xxx in the equation: log2(x−3)+log2(x+3)=2log2(x−1)\log_2(x - 3) + \log_2(x + 3) = 2\log_2(x - 1)log2(x−3)+log2(x+3)=2log2(x−1).
x=5x = 5x=5
x=3x = 3x=3
x=4x = 4x=4
No real solution