Solve for xxx: xx−4+2x+3=x2+8x2−x−12\frac{x}{x-4} + \frac{2}{x+3} = \frac{x^2+8}{x^2-x-12}x−4x+x+32=x2−x−12x2+8.
x=0x=0x=0
x=4x=4x=4
x=8x=8x=8
No solution