Solve for xxx: x−3x+x+3x+2=2\frac{x-3}{x} + \frac{x+3}{x+2} = 2xx−3+x+2x+3=2.
x=3x = 3x=3
x=−3x = -3x=−3
x=6x = 6x=6
x=−6x = -6x=−6