Solve for xxx: xx−3−2x+1=x2(x−3)(x+1)\frac{x}{x-3} - \frac{2}{x+1} = \frac{x^2}{(x-3)(x+1)}x−3x−x+12=(x−3)(x+1)x2
x=2x = 2x=2
x=−2x = -2x=−2 or x=3x = 3x=3
x=0x = 0x=0 or x=2x = 2x=2
x=1x = 1x=1