Solve for xxx: e2x−7ex+12=0e^{2x} - 7e^x + 12 = 0e2x−7ex+12=0
x=ln(3)x = \ln(3)x=ln(3) or x=ln(4)x = \ln(4)x=ln(4)
x=ln(2)x = \ln(2)x=ln(2) or x=ln(6)x = \ln(6)x=ln(6)
x=ln(3)x = \ln(3)x=ln(3) only
no solutions