Solve for xxx: \acxx−1−\ac2x+1=\ac4x−2x2−1\ac{x}{x-1} - \ac{2}{x+1} = \ac{4x-2}{x^2 - 1}\acxx−1−\ac2x+1=\ac4x−2x2−1.
4
0
Both a and b
No solution