Solve for xxx: \acx+2x−2−\acx−2x+2=\ac16x2−4\ac{x+2}{x-2} - \ac{x-2}{x+2} = \ac{16}{x^2 - 4}\acx+2x−2−\acx−2x+2=\ac16x2−4.
2
-2
4
No solution