Solve for xxx: 32x−4⋅3x+3=03^{2x} - 4 \cdot 3^x + 3 = 032x−4⋅3x+3=0.
x=0x = 0x=0 or x=log3(3)x = \log_3(3)x=log3(3)
x=1x = 1x=1 or x=0x = 0x=0
x=log3(2)x = \log_3(2)x=log3(2) or x=1x = 1x=1
x=−1x = -1x=−1 or x=2x = 2x=2