Solve for xxx: 32x−12⋅3x+27=03^{2x} - 12 \cdot 3^x + 27 = 032x−12⋅3x+27=0.
x=1x = 1x=1 or x=2x = 2x=2
x=0x = 0x=0 or x=1x = 1x=1
x=1x = 1x=1 or x=log3(9)x = \log_3(9)x=log3(9)
x=log3(3)x = \log_3(3)x=log3(3) or x=log3(9)x = \log_3(9)x=log3(9)