Solve for xxx: 2x2+5x−3≤02x^2 + 5x - 3 \leq 02x2+5x−3≤0.
x∈[−3,0.5]x \in [-3, 0.5]x∈[−3,0.5]
x∈(−3,0.5)x \in (-3, 0.5)x∈(−3,0.5)
x∈(−∞,−3]∪[0.5,∞)x \in (-\infty, -3] \cup [0.5, \infty)x∈(−∞,−3]∪[0.5,∞)
x∈[−0.5,3]x \in [-0.5, 3]x∈[−0.5,3]