Solve for xxx: 2x=3x−12^{x} = 3^{x-1}2x=3x−1.
x=ln3ln3−ln2x = \frac{\ln 3}{\ln 3 - \ln 2}x=ln3−ln2ln3
x=ln2ln3x = \frac{\ln 2}{\ln 3}x=ln3ln2
x=ln3−ln2x = \ln 3 - \ln 2x=ln3−ln2
x=13x = \frac{1}{3}x=31