Solve for xxx: 2[3x−(x−1)]=5[x+2(1−x)]2[3x - (x - 1)] = 5[x + 2(1 - x)]2[3x−(x−1)]=5[x+2(1−x)].
−8/9-8/9−8/9
−12/9-12/9−12/9
1/31/31/3
−1-1−1