Solve for xxx: 22x−6⋅2x+8=02^{2x} - 6 \cdot 2^x + 8 = 022x−6⋅2x+8=0. Which of the following are valid solutions?
x=1x = 1x=1
x=2x = 2x=2
x=4x = 4x=4
x=3x = 3x=3