Solve for uuu: uu+3+2u−1=1\frac{u}{u+3} + \frac{2}{u-1} = 1u+3u+u−12=1.
u=3u = 3u=3
u=−3u = -3u=−3
u=5u = 5u=5
u=−5u = -5u=−5