Solve for θ\thetaθ in the interval [0,2pi][0, 2pi][0,2pi]: sin(2θ)=cos(θ)sin(2\theta) = cos(\theta)sin(2θ)=cos(θ).
pi/6pi/6pi/6
pi/2pi/2pi/2
5pi/65pi/65pi/6
3pi/23pi/23pi/2