Solve for the set of all xxx such that x−2x+3≥0\frac{x-2}{x+3} \geq 0x+3x−2≥0.
(−∞,−3)∪[2,∞)(-\infty, -3) \cup [2, \infty)(−∞,−3)∪[2,∞)
(−3,2](-3, 2](−3,2]
[2,∞)[2, \infty)[2,∞)
(−∞,−3](-\infty, -3](−∞,−3]