Solve for the real value(s) of xxx in the equation: logx(3x+10)−logx(x+2)=1\log_x(3x + 10) - \log_x(x + 2) = 1logx(3x+10)−logx(x+2)=1.
x=5x = 5x=5
x=2x = 2x=2
x=5x = 5x=5 and x=−2x = -2x=−2
No real solution