Solve for the real value of xxx: logx(3x+4)=2\log_{x}(3x+4) = 2logx(3x+4)=2.
x=4x = 4x=4
x=−1,4x = -1, 4x=−1,4
x=1,4x = 1, 4x=1,4
x=4,−1/2x = 4, -1/2x=4,−1/2