Solve for the range of θ\thetaθ in the inequality: tan2(θ)<3\tan^2(\theta) < 3tan2(θ)<3 for 0≤θ<π0 \leq \theta < \pi0≤θ<π.
0≤θ<π30 \leq \theta < \frac{\pi}{3}0≤θ<3π or 2π3<θ<π\frac{2\pi}{3} < \theta < \pi32π<θ<π
0≤θ<π60 \leq \theta < \frac{\pi}{6}0≤θ<6π or 5π6<θ<π\frac{5\pi}{6} < \theta < \pi65π<θ<π
π3<θ<2π3\frac{\pi}{3} < \theta < \frac{2\pi}{3}3π<θ<32π
π6<θ<5π6\frac{\pi}{6} < \theta < \frac{5\pi}{6}6π<θ<65π