Solve for the integrating factor μ(x,y)\mu(x,y)μ(x,y) for the equation (3x2y+2xy+y3)dx+(x2+y2)dy=0(3x^2y + 2xy + y^3)dx + (x^2 + y^2)dy = 0(3x2y+2xy+y3)dx+(x2+y2)dy=0.
μ=e3x\mu = e^{3x}μ=e3x
μ=x3\mu = x^3μ=x3
μ=ex3\mu = e^{x^3}μ=ex3
μ=x2\mu = x^2μ=x2