Solve for c1c_1c1 and c2c_2c2 in the solution an=c1⋅3n+c2⋅2na_n = c_1 \cdot 3^n + c_2 \cdot 2^nan=c1⋅3n+c2⋅2n given a0=8a_0 = 8a0=8 and a1=15a_1 = 15a1=15.
c1=2,c2=6c_1 = 2, c_2 = 6c1=2,c2=6
c1=3,c2=5c_1 = 3, c_2 = 5c1=3,c2=5
c1=1,c2=7c_1 = 1, c_2 = 7c1=1,c2=7
c1=4,c2=4c_1 = 4, c_2 = 4c1=4,c2=4